## Dynamics

Apologies:

I am not very tech savvy. Some minor issues with the quizes like ‘\hfill’ keeps appearing, not being able to put in lengthy explanations and some math terms not showing up properly. Please forgive me. Just ignore the ‘\hfill’, check the bottom of the page to see if there are any explanations for the questions which you are not sure of and refresh the page (press F5 on keyboard) if the math terms are not showing up properly. Thank you and have fun!

## Dynamics (O Level)

*Dynamics (O Level)*. You scored %%SCORE%% out of %%TOTAL%%. Your performance has been rated as %%RATING%%

Question 1 |

$2m{s^{ - 2}}$ | |

$4m{s^{ - 2}}$ | |

$6m{s^{ - 2}}$ | |

$8m{s^{ - 2}}$ |

Question 2 |

0.67 N | |

1.5 N | |

2 N | |

24 N |

Question 3 |

$0.5m{s^{ - 2}}$ | |

$0.67m{s^{ - 2}}$ | |

$1.5m{s^{ - 2}}$ | |

$2m{s^{ - 2}}$ |

Question 4 |

$0.5m{s^{ - 2}}$ | |

$0.75m{s^{ - 2}}$ | |

$1.75m{s^{ - 2}}$ | |

$3m{s^{ - 2}}$ |

Question 5 |

$0m{s^{ - 2}}$ | |

$0.75m{s^{ - 2}}$ | |

$2m{s^{ - 2}}$ | |

$2.5m{s^{ - 2}}$ |

Question 6 |

The ball will stop immediately | |

The ball will slow to a stop | |

The ball will continue at its original speed | |

The ball will increase in speed |

Question 7 |

$1m{s^{ - 2}}$ | |

$1.33m{s^{ - 2}}$ | |

$3m{s^{ - 2}}$ | |

$4m{s^{ - 2}}$ |

Question 8 |

2 N Hint: 6 | |

4 N | |

6 N | |

8 N |

Question 9 |

2 N | |

4 N | |

6 N | |

8 N |

Question 10 |

3 N | |

4 N | |

5 N | |

6 N |

Question 11 |

\[1.67m{s^{ - 2}}\] | |

\[3.75m{s^{ - 2}}\] | |

\[8m{s^{ - 2}}\] | |

\[10m{s^{ - 2}}\] |

Question 12 |

\[2.5m{s^{ - 2}}\] | |

\[3.33m{s^{ - 2}}\] | |

\[5m{s^{ - 2}}\] | |

\[10m{s^{ - 2}}\] |

Question 13 |

5N, \[{36.9^o}\] East of South | |

5N, \[{36.9^o}\] West of South | |

7N, \[{36.9^o}\] East of South | |

7N, \[{36.9^o}\] West of South |

Question 14 |

2.1 | |

2.6 | |

3.2 | |

4.8 |

## More Explainations

**Qn 13**

Horizontal component of diagonal force:

\[\begin{gathered}

\cos {30^o} = \frac{{{F_h}}}{3} \hfill \\

{F_h} = 2.60 \hfill \\

\end{gathered} \]

Vertical component of diagonal force:

\[\begin{gathered}

\sin {30^o} = \frac{{{F_v}}}{3} \hfill \\

{F_v} = 1.5 \hfill \\

\end{gathered} \]

Resultant horizontal force:

\[4 - 2.6 = 1.4\]

Resultant vertical force:

\[3 - 1.5 = 1.5\]

Resultant force:

\[\begin{gathered}

{F_r}^2 = {(1.4)^2} + {(1.5)^2} \hfill \\

{F_r} = 2.05 \approx 2.1 \hfill \\

\end{gathered} \]